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21 September, 14:07

The molar mass of glucose is 180.2 g/mol. How many grams of glucose will be produced when 132.0 g of CO2 reacts with an excess of water?

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  1. 21 September, 14:10
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    The mass in grams of glucose produced when 132.0 g of CO2 reacts with an excess of water is 90.1 grams

    Explanation:

    The chemical equation for the reaction is

    6H₂O + 6CO₂ → C₆H₁₂O₆ + 6O₂

    From the reaction, it is seen that 6 moles of H₂O reacts ith 6 moles of CO₂ to produce 1 mole of glucose C₆H₁₂O₆ and 6 moles oxygen gas

    The molar mass of CO₂ = 44.01 g/mol

    There fpre 132.0 g contains 132.0/44.01 moles or ≅ 3 moles

    However since 6 moles of CO₂ produces 1 mole of O₂, then 3 moles of CO₂ will prduce 1/6*3 or 0.5 moles of C₆H₁₂O₆

    and since the molar mass (or the mass of one mole) of C₆H₁₂O₆ is 180.2 grams/mole then 0.5 mole of C₆H₁₂O₆ will have a mass of

    mass of 1 mole C₆H₁₂O₆ = 180.2 g

    mass of 0.5 mole C₆H₁₂O₆ = 180.2 g * 0.5 = 90.1 grams

    Mass of glucose produced = 90.1 grams
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