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14 October, 08:00

In the reaction of Zn with HCI, 140.15 g of ZnCl2 was actually formed, although the theoretical yield

was 143 g. What was the percent yield?

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Answers (1)
  1. 14 October, 08:28
    0
    Percent yield of ZnCl₂ = 98 %

    Explanation:

    Data Given:

    Actual yield of ZnCl₂ = 140.15 g

    Theoretical yield of ZnCl₂ = 143 g.

    percent yield = ?

    Solution:

    Formula used

    Percent yield = Actual yield / Theoretical yield x 100%

    Put values in the formula

    Percent yield = 140.15 g / 143 g x 100%

    Percent yield = 98.007 %

    Rounded to significant figure

    Percent yield of ZnCl₂ = 98 %
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