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5 February, 21:03

if a sample of gas at 25.2°C has a volume of 536 ml at 637 torr, what will its volume be if the pressure is increased to 712 torr?

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  1. 5 February, 21:22
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    V = 479.6 mL

    Explanation:

    assuming ideal gas:

    PV = RTn

    ∴ T = 25.2°C ≅ 298.2 K ... remains constant

    ∴ P1 = 637 torr = 0.8382 atm

    ∴ V1 = 536 mL = 0.536 L

    ∴ R = 0.082 atm. L/K. mol

    ⇒ n = (P1V1) / (RT) = ((0.8382 atm) * (0.536 L)) / ((0.082 atmL/Kmol) * (298.2K))

    ⇒ n = 0.0184 mol ... remains constant

    ∴ P2 = 712 torr = 0.936842 atm

    ⇒ V2 = RTn/P2 = [ (0.082atmL/Kmol) * (298.2K) * (0.0184mol) ] / (0.936842atm)

    ⇒ V2 = 0.4796 L
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