What's the molarity of the solution containing 10 g of NaCN in 250 mL of solution?

0.816

Explanation:

1 mole of NaCN is

Na = 23

C = 12

N = 14

Total = 49 grams / mole (just add 23 + 12 + 14)

moles when only 10 grams of NaCN are used.

moles = grams/molar mass

grams = 10

molar mass = 49

moles = 10 / 49

moles = 0.204 moles

Volume in Liters

250 mL = 250mL/1000 mL / Liter = 0.25 Liters

Molarity

M = m/V

M = 0.204/0.25 = 0.816