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4 January, 00:14

The ph of a 0.24 m solution of dimethylamine is 12.01. calculate the kb value for dimethylamine.

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  1. 4 January, 00:22
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    1 - First we will get the value of POH from:

    PH + POH = 14

    and we have PH = 12.01

    ∴ POH = 14 - 12.01 = 1.99

    2 - Then we need to get the concentration of OH:

    when POH = - ㏒[OH]

    1.99 = - ㏒[OH]

    ∴[OH] = 0.01 M

    now we have the concentration at Equ by subtracting from the initial concentration of OH = 0.24 M

    ∴ [OH] = 0.24 - 0.01 = 0.23 M

    ∴ Kb = (0.01) ^2 / 0.22977 M

    ∴ Kb value = 4.4 x 10^-4
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