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5 February, 19:21

a sample of gas at a pressure of 5.1 atm and a temperature of 45 degrees celsius is heated. it's pressure goes to 7.8 atm what is it's new temperature in celsius

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  1. 5 February, 19:47
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    213.4°C.

    Explanation:

    Data obtained from the question:

    Initial pressure (P1) = 5.1atm

    Initial temperature (T1) = 45°C = 45°C + 273 = 318K

    Final pressure (P2) = 7.8atm

    Final temperature (T2) = ... ?

    The new temperature can be obtained as follow:

    P1/T1 = P2 / T2

    5.1/318 = 7.8/T2

    Cross multiply

    5.1 x T2 = 318 x 7. 8

    Divide both side by 5.1

    T2 = 318 x 7. 8 / 5.1

    T2 = 486.4K

    Finally, we shall convert 486.4K to celsius temperature. This can be done as follow:

    T (°C) = T (K) - 273

    T (K) = 486.4K

    T (°C) = 486.4 - 273

    T (°C) = 213.4°C.

    Therefore, the new temperature is 213.4°C
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