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13 December, 06:20

A weather balloon at Earth's surface has a volume of 3.9 L at 299 K and 763 mmHg. If the balloon is released and the volume reaches 4.13 L at 720 mmHg, what is the temperature? Answer in units of K.

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  1. 13 December, 06:49
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    Combined Gas Laws

    Given: V1 = 3.9L V2 = 4.13L T1 = 299K P1=763mmHg P2=720mmHg

    Unknown: T2=?

    Formula: T2=T1P2V2 / P1V1

    Solution: T2 = (299K) (720mmHg) (4.13L) / (763mmHg) (3.9L)

    = 889,106.4 / 2975.7

    Answer: T2=298.8K
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