A sample of 0.53 g of carbon dioxide was obtained by heating 1.31 g of calcium carbonate. what is the percent yield for this reaction? caco3 (s) ⟶ cao (s) + co2 (s)

Question

Troy Fritz

Chemistry

20 November, 09:20

A sample of 0.53 g of carbon dioxide was obtained by heating 1.31 g of calcium carbonate. what is the percent yield for this reaction? caco3 (s) ⟶ cao (s) + co2 (s)

+4

Answers (1)

Know the Answer?

Laylah Weeks · Answer 1

CaCO3 (s) ⟶ CaO (s) + CO2 (s)

moles CaCO3: 1.31 g/100 g/mole CaCO3 = 0.0131

From stoichiometry, 1 mole of CO2 is formed per 1 mole CaCO3, therefore 0.0131 moles CO2 should also be formed.

0.0131 moles CO2 x 44 g/mole CO2 = 0.576 g CO2

Therefore:

% Yield: 0.53/.576 x100 = 92 percent yield