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25 March, 19:21

The proposed mechanism for the reaction ClO - (aq) + I - (aq) - -> IO - (aq) + Cl - (aq) is

1. ClO - (aq) + H2O (l) HClO (aq) + OH - (aq) FAST

2. I - (aq) + HClO (aq) HIO (aq) + Cl - (aq) FAST

3. OH - (aq) + HIO (aq) = > H2O (l) + IO - (aq) SLOW

What is the overall equation? (Type your answer using the format [NH4] + for NH4+. Use the lowest possible coefficients. Enter 0 if necessary. Do not leave any box blank.)

(aq) + I - (aq) Cl - (aq) + (aq) (b) Identify the intermediates, if any.

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Answers (1)
  1. 25 March, 19:51
    0
    1 ClO - (aq) + 1 I - (aq) - --> 1 Cl - (aq) + 1 IO - (aq).

    Explanation:

    1. ClO - (aq) + H2O (l) HClO (aq) + OH - (aq)

    2. I - (aq) + HClO (aq) HIO (aq) + Cl - (aq)

    3. OH - (aq) + HIO (aq) = > H2O (l) + IO - (aq)

    Adding all the 3 equations together gives and it gives:

    ClO - (aq) + H2O (l) + I - (aq) + HClO (aq) + OH - (aq) + HIO (aq)

    ---> HClO (aq) + OH - (aq) + HIO (aq) + Cl - (aq) + H2O (l) + IO - (aq)

    Deleting the same species on both sides of the equation gives:

    1 ClO - (aq) + 1 I - (aq) - --> 1 Cl - (aq) + 1 IO - (aq)

    The overall equation:

    1 ClO - (aq) + 1 I - (aq) - --> 1 Cl - (aq) + 1 IO - (aq)
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