The proposed mechanism for the reaction ClO - (aq) + I - (aq) - -> IO - (aq) + Cl - (aq) is

1. ClO - (aq) + H2O (l) HClO (aq) + OH - (aq) FAST

2. I - (aq) + HClO (aq) HIO (aq) + Cl - (aq) FAST

3. OH - (aq) + HIO (aq) = > H2O (l) + IO - (aq) SLOW

What is the overall equation? (Type your answer using the format [NH4] + for NH4+. Use the lowest possible coefficients. Enter 0 if necessary. Do not leave any box blank.)

(aq) + I - (aq) Cl - (aq) + (aq) (b) Identify the intermediates, if any.

1 ClO - (aq) + 1 I - (aq) - --> 1 Cl - (aq) + 1 IO - (aq).

Explanation:

1. ClO - (aq) + H2O (l) HClO (aq) + OH - (aq)

2. I - (aq) + HClO (aq) HIO (aq) + Cl - (aq)

3. OH - (aq) + HIO (aq) = > H2O (l) + IO - (aq)

Adding all the 3 equations together gives and it gives:

ClO - (aq) + H2O (l) + I - (aq) + HClO (aq) + OH - (aq) + HIO (aq)

---> HClO (aq) + OH - (aq) + HIO (aq) + Cl - (aq) + H2O (l) + IO - (aq)

Deleting the same species on both sides of the equation gives:

1 ClO - (aq) + 1 I - (aq) - --> 1 Cl - (aq) + 1 IO - (aq)

The overall equation:

1 ClO - (aq) + 1 I - (aq) - --> 1 Cl - (aq) + 1 IO - (aq)