Ask Question
28 March, 14:15

You place a balloon in a closed chamber at standard temperature and pressure (STP). You cool the chamber to half of its original temperature while leaving the pressure constant. What happens to the balloon?

It stays the same volume.

It decreases to one-half of its original volume.

It doubles in volume.

It expands to four times its original volume.

+4
Answers (2)
  1. 28 March, 14:22
    0
    It decreases to one half of its original volume.
  2. 28 March, 14:35
    0
    I think the correct answer from the choices listed above is the second option. At constant temperature, the volume of the system at the new conditions will decrease to one-half of its original volume.

    V1 = nRT1 / P

    V2 = nRT1 / 2P = 2V1
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “You place a balloon in a closed chamber at standard temperature and pressure (STP). You cool the chamber to half of its original ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers