You place a balloon in a closed chamber at standard temperature and pressure (STP). You cool the chamber to half of its original temperature while leaving the pressure constant. What happens to the balloon?

It stays the same volume.

It decreases to one-half of its original volume.

It doubles in volume.

It expands to four times its original volume.

Question

Julian Price

Chemistry

28 March, 14:15

You place a balloon in a closed chamber at standard temperature and pressure (STP). You cool the chamber to half of its original temperature while leaving the pressure constant. What happens to the balloon?

It stays the same volume.

It decreases to one-half of its original volume.

It doubles in volume.

It expands to four times its original volume.

+4

Answers (2)

Know the Answer?

Janessa Shepard · Answer 1

It decreases to one half of its original volume.

Steven Jefferson · Answer 2

I think the correct answer from the choices listed above is the second option. At constant temperature, the volume of the system at the new conditions will decrease to one-half of its original volume.

V1 = nRT1 / P

V2 = nRT1 / 2P = 2V1