If you only have 5.25mol of Copper and excess AgNO3, how many moles of silver can be produced?

10.5moles of Ag

Explanation:

Equation of reaction

Cu + 2AgNO₃ → Cu (NO₃) ₂ + 2Ag

The above reaction is a example of displacement reaction.

From the chemical equation,

1 mole of Cu will produce 2 moles of Ag

1 mole Cu = 2moles Ag

5.25moles of Cu = x moles of Ag

X = (2 * 5.25) / 1

5.25moles of Cu will produce 10.5 moles of Ag