If 4520 kj of heat is needed to boil a sample of water, what is the mass of water

1,085g of water

Explanation:

If we have the value 4520kj is because the question is related to Energy and heat capacity. In this case, the law and equation that we use is the following:

Q = m*C*Δt where;

Q in the heat, in this case: 4520kj

m is the mas

Δt = is the difference between final-initial temperature (change of temperature), in this exercise we don't have temperatura change.

In order to determine the mass, I will have the same equation but finding m

m = Q/C*Δt without m=Q/C

So: m = 4,520J/4.18J/g°C

m = 1,0813 g