Ask Question
4 January, 12:36

What volume of propane (C3H8) is required to produce 165 liters of water according to the following reaction? (All gases are at the same temperature and pressure.) propane (C3H8) (g) + oxygen (g) carbon dioxide (g) + water (g)

+3
Answers (1)
  1. 4 January, 12:55
    0
    We need 41.2 L of propane

    Explanation:

    Step 1: Data given

    volume of H2O = 165 L

    Step 2: The balanced equation

    C3H8 (g) + 5O2 (g) → 3CO2 (g) + 4H2O (g)

    Step 3: Calculate moles of H2O

    1 mol = 22.4 L

    165 L = 7.37 moles

    Step 4: Calculate moles of propane

    For 1 mol C3H8 we need 5 moles O2 to produce 3 moles CO2 and 4 moles H2O

    For 7.37 moles H2O we need 7.37/4 = 1.84 moles propane

    Step 5: Calculate volume of propane

    1 mol = 22.4 L

    1.84 moles = 41.2 L

    We need 41.2 L of propane
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “What volume of propane (C3H8) is required to produce 165 liters of water according to the following reaction? (All gases are at the same ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers