Ask Question
9 October, 12:29

Determine the concentrations of na2co3, na, and co32 - in a solution prepared by dissolving 1.80 * 10-4 g na2co3 in 2.25 l of water. express all three concentrations in molarity. additionally, express the concentrations of the ionic species in parts per million (ppm). note: determine the formal concentration of co32-. ignore any reactions with water.

+5
Answers (1)
  1. 9 October, 12:35
    0
    First, we write the equation for the dissolution of sodium carbonate.

    Na₂CO₃ (s) → 2Na⁺ (aq) + CO₃⁻² (aq)

    Next, we determine the moles of sodium carbonate that have been dissolved. The molar mass of sodium carbonate is 106 g/mol.

    Moles = mass / Mr

    Moles = 1.8 x 10⁻⁴ / 106

    Moles = 1.70 x 10⁻⁶ moles

    The moles of sodium ions will be double this, as observed in the equation, while the moles of carbonate ions will be equivalent to this.

    The molarity of a substance is the number of moles per liter. The ppm of a substance is the milligrams of the substance per liter of water. Using these definitions,

    Molarity Na₂CO₃ = 1.7 x 10⁻⁶ / 2.25 = 7.6 x 10⁻⁷ M

    Molarity Na + = 2 * 1.7 x 10⁻⁶ / 2.25 = 1.52 x 10⁻⁶ M

    Molarity CO₃⁻² = 1.7 x 10⁻⁶ / 2.25 = 7.6 x 10⁻⁷ M

    PPM Na₂CO₃ = 0.18 mg / 2.25 liters = 0.08 ppm

    PPM Na⁺ = moles * molar mass in mg / liters

    PPM Na⁺ = 2 * 1.7 x 10⁻⁶ * 23000 / 2.25 = 0.035 ppm

    PPM CO₃⁻² = moles * molar mass in mg / liters

    PPM CO₃⁻² = 1.7 x 10⁻⁶ * 60000 / 2.25 = 0.045 ppm
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Determine the concentrations of na2co3, na, and co32 - in a solution prepared by dissolving 1.80 * 10-4 g na2co3 in 2.25 l of water. ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers