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22 March, 04:47

Quicklime (CaO) is produced by the thermal decomposition of calcium carbonate (CaCO3). Calculate the volume of CO2 at STP produced from the decomposition of 152 g CaCO3 by the reaction.

CaCO3 - > CaO + CO2

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  1. 22 March, 05:16
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    V = 34.1 L

    Explanation:

    Given dа ta:

    Mass of CaCO₃ = 152 g

    Volume of CO₂ produced = ?

    Solution:

    Chemical equation:

    CaCO₃ → CaO + CO₂

    Number of moles of CaCO₃:

    Number of moles = mass / molar mass

    Number of moles = 152 g / 100 g/mol

    Number of moles = 1.52 mol

    Now we will compare the moles of CaCO₃ with CO₂

    CaCO₃ : CO₂

    1 : 1

    1.52 : 1.52

    Volume of CO₂:

    PV = nRT

    Standard temperature = 273 K

    Standard pressure = 1 atm

    R = 0.0821 atm. L/mol. K

    Now we will put the value sin formula:

    V = nRT/P

    V = 1.52 mol * 0.0821 atm. L/mol. K * 273 K / 1 atm

    V = 34.1 L
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