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13 December, 19:29

A solution was prepared by dissolving 0.05000 mol of sucrose in 100.0 kg of water. Find

the molality of the solution.

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Answers (2)
  1. 13 December, 19:30
    0
    0.0005mol/kg

    Explanation:

    Molality = mole of solute/mass of solvent (kg)

    From the question, we obtained the following dа ta:

    Mole of solute = 0.05mole

    Mass of solvent = 100kg

    Molality = 0.05/100

    Molality = 0.0005mol/kg

    The molality of the solution is 0.0005mol/kg
  2. 13 December, 19:52
    0
    Answer: 5x10-4 mole / kg

    Explanation: Molality is expressed as number of moles per unit kilograms of solvent.

    m = n / kg

    = 0.05000 mole / 100.0 kg

    = 0.0005 m or 5x10-4 mole / kg
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