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5 February, 22:41

How do you prepare a 250 mL of a 2.35 M HF dilution from a 15.0 M solution

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  1. 5 February, 22:45
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    In dilution problems involving known concentrations and volumes of the solution, a widely used equation is:

    C1V1 = C2V2

    Where:

    C1 = Concentration of Solution 1

    V1 = Volume of Solution 1

    C2 = Concentration of Solution 2

    V2 = Volume of Solution 2

    Substituting the given values gives: (2.35 M) * (250mL) = (15.0 M) * V2

    V2 = 39.17 mL

    So, you must initially have 39.17 mL of 15 M solution and dilute it to 250 mL to achieve a 2.35 M solution
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