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23 September, 06:52

Ethene is converted to ethane by the reaction C2H4 1g2 1 H2 1g2 8888n C2H6 1g2 C2H4 flows into a catalytic reactor at 25.0 atm and 300.8C with a flow rate of 1000. L/min. Hydrogen at 25.0 atm and 300.8C flows into the reactor at a flow rate of 1500. L/min. If 15.0 kg C2H6 is collected per minute, what is the percent yield of the reaction

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  1. 23 September, 07:13
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    Percentage Yield = 93.8%

    Explanation:

    dа ta:

    R = 0.08206 L. atm/mol/K,

    Molar mass of C2H6 = 30.08 g/mol

    T = 300° c + 273K = 573.15 K

    C2H4 Conditions,

    P = 25 atm

    V = 1000 L/min

    H2 Condition,

    P = 25 atm

    V = 1500 L/min

    Solution:

    First we will calculate the moles of ethane produced in one minute,

    nC2H6 = (15/30.08) (1000/1)

    nC2H6 = 498.67 mol/min

    Now we will calculate the moles of ethane flowing in one minute using the ideal gas equation which is, Pv = nRT

    n = pV/R

    nC2H4 = ((25 * 1000) / (0.08206*573.15))

    nC2H4 = 531.54 mol/min

    Similarly Calculating the moles of hydrogenflowing in one minute,

    nH2 = ((25*1500) / (0.08206) (573.15))

    nH2 = 797.32 mol/mim

    Both hydrogen and ethene are flowing at 25 atm and 573.15 K but the flow rate of hydrogen is more than that of ethane which results in less amount of available ethene for the reaction. We know that 1 mole of ethene reacts with 1 mole of hydrogen to give 1 mole of ethane

    hence ethene is acting as the limiting reagent here

    Now calculating the %Yield = (498.67/531.54) * 100

    %Yield = 93.82%
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