Suppose you wanted to dissolve 109 g of sodium carbonate in enough water to make 6.00 L of solution. What is the molarity of this solution?

Molarity

a. Na2CO3

Molar mass = 106 g/mol

n = 109 g / (106 g/mol) = 1.028 mol

b. 6.00L

c. M=n/V

M = 1.028 mol / 6.00 L

M = 0.1713 mol / L

Answer: The molarity of the sodium carbonate solution is 0.1713 mol/L