Ask Question
2 December, 07:05

What is the mass of water required to prepare 250.0 g of 10.0% copper (ii) sulfate solution?

+5
Answers (1)
  1. 2 December, 07:27
    0
    Answer is: mass of water needed for preparation of copper (II) sulfate solution is 225 grams.

    mr (CuSO ₄) = 250.0 g.

    ω (CuSO₄) = 10.0% : 100% = 0.1.

    m (CuSO₄) = mr (CuSO₄) · ω (CuSO₄).

    m (CuSO₄) = 250 g · 0.1.

    m (CuSO₄) = 25 g.

    m (H₂O) = mr (CuSO₄) - m (CuSO₄).

    m (H₂O) = 250 g - 25 g.

    m (H₂O) = 225 g.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “What is the mass of water required to prepare 250.0 g of 10.0% copper (ii) sulfate solution? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers