Ask Question
13 June, 16:06

How many grams of O2 (g) are needed to completely burn 39.1 g of C3H8 (g) ?

+4
Answers (1)
  1. 13 June, 16:31
    0
    The formula is

    CxHy + (x+y/4) O2=xCO2+yH2O

    the molecular weight of C3H8 is 44 gm so according the formula (5*32) gm O2 are needed to completely burn 44gm C3H8 so for 39.1 gm C3H8 we needed (39.1*32*5) / (44) = 142.181 gm
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “How many grams of O2 (g) are needed to completely burn 39.1 g of C3H8 (g) ? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers