Ask Question
30 June, 23:35

What volume of 3.3 m hno3 solution is needed to completely neutralize 175 ml of a 4.10 m koh solution?

+2
Answers (1)
  1. 30 June, 23:42
    0
    HNO₃ + KOH = KNO₃ + H₂O

    c (HNO₃) = 3.3 mol/L

    c (KOH) = 4.10 mol/L

    v (KOH) = 175 mL = 0.175 L

    n (KOH) = n (HNO₃)

    n (KOH) = c (KOH) v (KOH)

    n (HNO₃) = c (HNO₃) v (HNO₃)

    c (KOH) v (KOH) = c (HNO₃) v (HNO₃)

    v (HNO₃) = c (KOH) v (KOH) / c (HNO₃)

    v (HNO₃) = 4.10*0.175/3.3=0.217 L = 217 mL
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “What volume of 3.3 m hno3 solution is needed to completely neutralize 175 ml of a 4.10 m koh solution? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers