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2 August, 10:49

What is the volume of 0.24 mol oxygen (O2) gas at 345 K and a pressure of 0.75 atm

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  1. 2 August, 10:53
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    We know that the ideal gas equation relates the pressure, volume, temperature, and moles of gases as:

    PV = nRT

    This is a combined gas law based on other gas law like Boyle's law, Charle's law, Avagadro's law, Gay Lussac's law

    P = pressure = 0.75 atm

    V = volume = ?

    n = moles = 0.24 mol

    R = 0.0821 L atm / molK [gas constant]

    T = temperature = 345 K

    Putting the values

    Volume = nRT / P

    Volume = 0.24 X 0.0821 X 345 / 0.75 = 9.06 L
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