How many liters of water vapor can be produced if 8.9 liters of methane gas (CH4) are combusted, if all measurements are taken at the same temperature and pressure? Show all of the work used to solve this problem.

CH4 (g) + 2 O2 (g) CO2 (g) + 2 H2O (g)

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Baby Cakes

Chemistry

5 July, 04:19

How many liters of water vapor can be produced if 8.9 liters of methane gas (CH4) are combusted, if all measurements are taken at the same temperature and pressure? Show all of the work used to solve this problem.

CH4 (g) + 2 O2 (g) CO2 (g) + 2 H2O (g)

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Alvaro Mckay · Answer 1

From the chemical equation given, one mole of CH4 yields two moles of water (H2O). If all the methane gas that is 8.9 L is combusted then the volume of water produced is the number of moles H2O times the volume of the methane gas used up, that is 8.9 L * 2 = 17.8 L of water produced.

How many liters of water vapor can be produced if 8.9 liters of methane gas (CH4) are combusted, if all measurements are taken at the same temperature and pressure? Show all of the work used to solve this problem.CH4 (g) + 2 O2 (g) CO2 (g) + 2 H2O (g)

How many liters of water vapor can be produced if 8.9 liters of methane gas (CH4) are combusted, if all measurements are taken at the same temperature and pressure? Show all of the work used to solve this problem.

CH4 (g) + 2 O2 (g) CO2 (g) + 2 H2O (g)