1. Find the percent composition of a compound that contains 1.10 g calcium, 0.888 g sulfur.

and 1.76 grams of oxygen in a 3.74 a sample of the compound

The compound contains 29.3 % calcium, 23.7 % sulfur and 47 % oxygen

Explanation:

Step 1: Data given

Mass of the compound = 3.74 grams

Mass of calcium in the compound = 1.10 grams

Mass of sulfur in the compound = 0.888 grams

Mass of oxygen in the compound = 1.76 grams

Step 2: Calculate percent composition

Mass of Calcium + Mass of sulfur + mass of oxygen = total mass of compound = 3.74 grams

% Caclium = (1.10 grams / 3.74 grams) * 100 % = 29.3 %

% sulfur = (0.888 grams / 3.74 grams) * 100 % = 23.7 %

% oxygen = (1.76 grams / 3.74 grams) * 100 % = 47%

29.3 % + 23.7 % + 47% = 100 %

The compound contains 29.3 % calcium, 23.7 % sulfur and 47 % oxygen