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17 December, 08:12

Find the mass, in grams, of 5.00*10^23 molecules of F2

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  1. 17 December, 08:34
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    Answer: 31.55 g

    Explanation:

    - The mass number of Fluoride atom (F) = 18.99 g/mol, so mass number of fluorine gas (F2) = 37.98 g/mol.

    - 1 mole of (F2) [which has 37.98 g/mol] contains Avogadro's number of molecules (6.02*10^23 molecules),

    so 1 mole of (F2) with 37.98 g/mol → 6.02*10^23 molecules.

    - Using cross multiplication,

    37.98 g/mol of (F2) → 6.02 * 10^23 molecules

    ? → 5.00 * 10^23 molecules

    Hence the mass of 5.00*10^23 molecules of F2 = (37.98 * 5.00 * 10^23) / 6.02 * 10^23 = 31.55 g ...
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