How many times does the following loop execute? int upperCaseLetters = 0; String str = "abcdEfghI"; boolean found = false; for (int i = 0; i < str. length () &&! found; i++) {char ch = str. charAt (i); if (Character. isUpperCase (ch)) {found = true; }}

Question

Braden

Computers & Technology

24 July, 23:49

How many times does the following loop execute? int upperCaseLetters = 0; String str = "abcdEfghI"; boolean found = false; for (int i = 0; i < str. length () &&! found; i++) {char ch = str. charAt (i); if (Character. isUpperCase (ch)) {found = true; }}

+4

Answers (1)

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Daniella Curry · Answer 1

Five times

Explanation:

Given the codes as follows:

int upperCaseLetters = 0; String str = "abcdEfghI"; boolean found = false; for (int i = 0; i < str. length () &&! found; i++) { char ch = str. charAt (i); if (Character. isUpperCase (ch)) { found = true; } }

The for loop will stop when the first uppercase letter is found in the str. This condition is set in the for loop condition (i < str. length () &&! found)

Since the the first upper case letter is the fifth character in the given str, the for loop will run for five rounds. In the fifth round the condition in the if statement (Line 9) will be evaluated to true and then set the true value to found variable (Line 11). This will terminate the loop in the next iteration.