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Write a program to test the difference between %d and %i conversion

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  1. 27 May, 03:19
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    Void test (char * s)

    {

    int i, d;

    sscanf (s, "%i", &i);

    printf ("%s converts to %i using %%i/n", s, i);

    sscanf (s, "%d", &d);

    printf ("%s converts to %d using %%d/n", s, d);

    }

    int main ()

    {

    test ("123");

    test ("0x123");

    return 0;

    }

    outputs:

    123 converts to 123 using %i

    123 converts to 123 using %d

    0x123 converts to 291 using %i

    0x123 converts to 0 using %d

    As you can see, %i is capable of parsing hexadecimal, whereas %d is not. For printf they're the same.
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