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Steven, Marcos, and Juan are having a free-throw shooting contest. Each boy

takes six turns and records the number of free throws he makes out of 10

shots. Which boy's median is greatest?

Steven: 2,4,6,8,8,9

Marcos: 3, 5, 6, 7, 8, 10

Juan: 3, 5, 5, 6,9,9

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Answers (1)
  1. 31 October, 09:52
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    Answer: Steven

    Explanation:

    Given the dа ta:

    Steven: 2, 4, 6, 8, 8, 9

    Marcos: 3, 5, 6, 7, 8, 10

    Juan: 3, 5, 5, 6, 9, 9

    The median value of an ungrouped data can be calculated or located using the relation:

    Median observation = (n + 1) / 2

    Whwre n) number of observations.

    If a Decimal value is obtained, the upper and lower bound of the observation is averaged to obtain the median value.

    Steven: 2, 4, 6, 8, 8, 9

    (6 + 1) / 2 = 7/2 = 3.5

    Therefore, the 3rd and 4th observations in the data is averaged.

    Median = (6+8) / 2 = 14/2 = 7

    Marcos: 3, 5, 6, 7, 8, 10

    (6 + 1) / 2 = 7/2 = 3.5

    Therefore, the 3rd and 4th observations in the data is averaged.

    Median = (6+7) / 2 = 13/2 = 6.5

    Juan: 3, 5, 5, 6,9,9

    (6 + 1) / 2 = 7/2 = 3.5

    Therefore, the 3rd and 4th observations in the data is averaged.

    Median = (5+6) / 2 = 11/2 = 5.5

    Therefore, Steven has the greatest median
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