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Mergesort uses the divide-and-conquer technique to sort a list.

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  1. 19 May, 22:33
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    True: Merge Sort sorts a list using divide-conquer approach.

    Merge_Sort (B, p, n) / /p is the starting index of array B and n is the last index.

    1. if (p
    2. q ← (p+n) / 2 / /divides the list into two sub-lists

    2. Merge_Sort (B, p, q) / /sorts the left half

    3. Merge_Sort (B, q+1, n) / /sorts the right half.

    4. Merge (B, p, q, n)

    Merge (B, p, q, n)

    1. l ← q-p+1. / /no. of elements in left half

    2. m ← n-q / /no. of elements in right half.

    3. for x ← 1 to l

    4. Left[x] = B[p+x - 1] / /The elements of left half are copied to Left array

    5. for y ← 1 to m.

    6. Right[y] = B[q+y] / /The elements of right half are copied to right array

    7. x ← 1, y ←1

    8. for z ← p to n.

    9. if (Left[x] ≤ Right[y]) / / to merge the two lists Left and Right, the / /elements are compared.

    10. { A[z] ← Left[x] / /smaller one comes to the merged list.

    11. x++. }

    12. else

    13. { A[z] ← Right[y]

    14. y+ + }

    Explanation:

    The Merge_Sort (A, p, n) algorithm first divides the whole array into two halves. Then again divides the sub-lists into it's halves and so on.

    Then using merge algorithm it compares the elements of both halves one by one and keep it in sorted order.
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