Ask Question

Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first collision, how long does the adapter wait until sensing the channel again for a 1 Mbps broadcast channel? For a 10 Mbps broadcast channel?

+5
Answers (1)
  1. 5 November, 05:41
    0
    Complete Question:

    Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first collision, if K=100, how long does the adapter wait until sensing the channel again for a 1 Mbps broadcast channel? For a 10 Mbps broadcast channel?

    Answer:

    a) 51.2 msec. b) 5.12 msec

    Explanation:

    If K=100, the time that the adapter must wait until sensing a channel after detecting a first collision, is given by the following expression:

    Tw = K*512 * bit time

    The bit time, is just the inverse of the channel bandwidh, expressed in bits per second, so for the two instances posed by the question, we have:

    a) BW = 1 Mbps = 10⁶ bps

    ⇒ Tw = 100*512 * (1/10⁶) bps = 51.2*10⁻³ sec. = 51.2 msec

    b) BW = 10 Mbps = 10⁷ bps

    ⇒ Tw = 100*512 * (1/10⁷) bps = 5.12*10⁻³ sec. = 5.12 msec
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first ...” in 📗 Computers & Technology if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers