What is the thermal energy contained within a cubic kilometre of granite (in barrels of oil equivalent) for every one degree change in temperature? Use the following parameters in your calculation: Specific heat of granite = 790 (J/kgC) Density of granite = 2700 kg/m3 Energy in 1 barrel of oil = 6.118e9 J

348643.34 barrels of oil

Explanation:

Given;

Volume of the granite = 1 km³ = 1000³ m³

Specific heat of granite, C = 790 J/kg.°C

Density of granite = 2700 kg/m³

Energy in 1 barrel of oil = 6.118 * 10⁹ J

For every 1° change in temperature, ΔT = 1°C

Now,

The thermal energy stored is given as;

Thermal energy = mCΔT

where, m is the mass

the mass of 1 km³ of granite = Density * Volume

or

the mass of 1 km³ of granite = 2700 * 1000³ = 27 * 10¹¹ Kg

therefore,

Thermal energy = 27 * 10¹¹ * 790 * 1

or

Thermal energy = 21330 * 10¹¹ J

hence,

the thermal energy in terms of barrels of oil

= Total thermal energy / Energy stored in 1 barrel of oil

= 21330 * 10¹¹ J / (6.118 * 10⁹ J per barrel)

= 348643.34 barrels of oil