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8 April, 17:01

A centrifugal Blower delivers 6m^3 of air per second against a head of 55mm of alcohol of relative density 0.79 when running at 400 RPM. Calculate the power required if the efficiency os 0.7. Estimate the discharge of a blower of similar design of twice the diameter when discharging against a head of 55mm of alcohol. Calculate the operating speed and the expected power. Air Density is 1.17Kg/m^3

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  1. 8 April, 17:26
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    speed is 200 rpm

    power is 14614.1 W

    Explanation:

    given data

    discharge Q = 6 m³

    head H = 55 mm

    running s = 400 rpm

    relative density R = 0.790 Kg/m³

    efficiency e = 0.7

    Air Density = 1.17 Kg/m³

    to find out

    speed and the expected power

    solution

    we will apply here 1s power formula that is

    power = Q * R * g * H / e ... 1

    put here all value

    power = 6 * 790 * 9.8 * 0.055 / 0.7

    power = 3653.52 W

    and we know discharge is directly proportional to square of diameter

    so

    Q1/Q2 = D1²/D2² ... 2

    here we know blower design twice the diameter so D2 is 2D

    6/Q2 = D² / (2D) ²

    so Q2 = 24 m³/s

    so speed is

    D1 * S = D2 * S1

    D * 400 = 2D * S1

    S1 = 200

    speed is 200 rpm

    and

    power is

    P1/P2 = Q1/Q2

    3653.52 / P2 = 6 / 24

    P2 = 14614.1

    so power is 14614.1 W
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