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8 April, 21:33

The specific volume of water vapor at 0.3 MPa, 160°C is 0.651 m3/kg. If the water vapor occupies a volume of 1.2 m3, determine the amount present, in kg.

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  1. 8 April, 21:52
    0
    1.84 kg

    Explanation:

    Data provided in the question:

    Specific volume of water vapor at 0.3 MPa, 160°C = 0.651 m³/kg

    Volume occupied by the water vapor = 1.2 m³

    Now,

    We know that the specific volume is given as:

    specific volume = Volume : Mass

    Therefore,

    Mass = [Volume ] : [ specific volume ]

    or

    Mass = 1.2 : 0.651

    or

    Mass = 1.84 kg
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