A person is attempting to start a 20hp diesel engine with a hand crank. The distance from the handle to the center of rotation is 12 inches. The person is able to apply 25 lbf tangent to the circular path of the handle. The crank rotates at 2 rounds per second. How much power (Btu/min and hp) is the person providing?

Question

Garrett

Engineering

4 October, 11:06

A person is attempting to start a 20hp diesel engine with a hand crank. The distance from the handle to the center of rotation is 12 inches. The person is able to apply 25 lbf tangent to the circular path of the handle. The crank rotates at 2 rounds per second. How much power (Btu/min and hp) is the person providing?

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Answers (1)

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Finley Cooke · Answer 1

Answer: 0.57 hp, 24.2 Btu/min

Explanation:

Hi!

The power P delivered when rotating a crank at angular speed ω, applying a torque τ is given by:

P = τ*ω

In this case torque is τ = 12 in * 25 lbf = 300 lbf*in

Angular speed is 2 round per seconds, which is 120 RPM. Then power is:

P = 300*120 lbf*in*RPM

1 hp = (lbf*in*RPM) / 63,025

P = 0.57 hp

1 hp = 42,4 Btu/min

Then P = 24.2 Btu/min