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15 June, 06:14

A gas pressure difference is applied to the legs of a U-tube manometer filled with a liquid with specific gravity of 1.7. The manometer reading is 320 mm. What is the pressure difference

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Answers (2)
  1. 15 June, 06:18
    0
    Answer : pressure difference is Δp=5,32pa

    Explanation : the expression for pressure difference at the top of the manometer can be given as

    P1-P2=Rg (ρm-ρs) ... 1

    For gases, ρs is negligibly small when compared to ρm. So substitute zero for in equation (1) and re-write the final expression

    Δp=Rg (ρm)

    Here,

    Δp is the differential pressure applied to manometer in Pa or psi

    R is the difference in the levels of the two interfaces in meters 320mm

    To metre = 0.320m

    g is the acceleration of gravity

    ρm is the manometer liquid density in 9.81m/s²

    Specific gravity (sg) of liquid 1.7

    Density of water is 997 kg/m³

    Sg=density of substance/density of water

    1.7=density of substance/997

    Density of substance=1.7*997

    =1694.9kg/m³

    Hence solving for pressure difference

    Δp=Rg (ρm)

    =0.320*9.81*1694.9

    Δp=5,32pa
  2. 15 June, 06:36
    0
    5320.6 Pascal

    Explanation:

    Manometer is a pressure measuring device use to measure gas pressure.

    Pressure difference in Manometer is a function of density, gravity and the height difference of the liquid.

    Pressure difference = density x acceleration due to gravity x difference in height of liquid

    Density of liquid = specific gravity of object x density of water.

    Density of water = 997 kg/m^3

    Specific gravity of liquid = 1.7

    Density of liquid = 997 x 1.7 = 1694.9kg/m^3

    g = 9.81 m/s^2

    h = 320mm = 0.320m

    Pressure difference = 1694.9 x 9.81 x 0.320 = 5320.6 Pascal
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