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6 September, 06:02

You are tasked to specify the flash storage device in General Electric's Data Logger Unit used in the smart power grid. The DLU records data from 4 processors. Each processor generates 16 KB of data per second. Sought: What is the sufficient capacity for the DLU to record 3 day s worth of data?

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  1. 6 September, 06:29
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    16.5888 GB

    Explanation:

    The smart power grid operates 24/7; since we want to store up to 3 days worth of data and every day has 86400 seconds we need to store a total of 259200 seconds of data; we have four devices operating continuously during that time and each processor generates 16 KB of data per second, therefore, the total data in one second is 16*4 = 64KB/seg. To find the storage S we multiply the time of operation by the data collected in one second - > S = 259200 seg * 64KB/seg = 16588800 KB equivalent to 16.5888 GB of data in three days for all processors.
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