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24 November, 07:28

An incoming signal is at a frequency of 500kHz. This signal needs to be acquired and all other signals attenuated. Design a passive bandpass filter to do this. Do this by combining a high pass and a low pass filter. For our purposes, create a pass band width of exactly 40kHz and is centered at the ideal frequency. R = 2kOhms. Select C[lowpass], enter value in terms of nF =

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  1. 24 November, 07:33
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    C_h = 0.166 nF

    C_L = 0.153 nF

    Explanation:

    Given:

    - Ideal frequency f_o = 500 KHz

    - Bandwidth of frequency BW = 40 KHz

    - The resistance identical to both low and high pass filter = 2 Kohms

    Find:

    Design a passive band-pass filter to do this by cascading a low and high pass filter.

    Solution:

    - First determine the cut-off frequencies f_c for each filter:

    f_c, L for High pass filter:

    f_c, L = f_o - BW/2 = 500 - 40/2

    f_c, L = 480 KHz

    f_c, h for Low pass filter:

    f_c, h = f_o + BW/2 = 500 + 40/2

    f_c, h = 520 KHz

    - Now use the design formula for R-C circuit for each filter:

    General design formula:

    f_c = 1 / 2*pi*R*C_i

    C, h for High pass filter:

    C_h = 1 / 2*pi*R*f_c, L

    C_h = 1 / 2*pi*2000*480,000

    C_h = 0.166 nF

    C, L for Low pass filter:

    C_L = 1 / 2*pi*R*f_c, h

    C_L = 1 / 2*pi*2000*520,000

    C_L = 0.153 nF
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