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6 August, 23:34

How much time does it take a freezer to make a tray of ice cubes out of a tray of 0.25kg liquid water at 10 Celsius). Assume the freezer is a constant cycle operating between-8 (Celsius) and 35 (Celsius) with a power requirement of 750 N. assume the liquid water is the only contents in the freezer

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  1. 7 August, 00:02
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    time = 20.27 second

    Explanation:

    Given data

    power = 750 N

    ice cube = 0.25 kg

    liquid water temp = 10°C

    cycle operating = - 8°C to 35°C

    to find out

    required time

    solution

    we know that latent heat of water i. e. h (w) = 333 kJ/kg

    and specific heat of water i. e S (p) = 4.187 kJ/kg

    so we find first heat remove from water (Q) i. e = mass (specific heat to water temp (10°C to 0°C) + latent heat of water)

    so Q = 0.25 (4.187 (10°C - 0°C) + 333)

    Q = 93.7175 kJ

    in question we have given

    Assume the freezer is a constant cycle operating so we consider here reversible carnot cycle

    so Coefficient of Performance = desired effect / work input = heat absorbed from evaporation / power

    so here desire effect is 273 - 8 = 265 and work input is 35 - (-8) = 43

    power is 0.75

    so heat absorbed from evaporation = 265 / 43 * 0.75

    heat absorbed from evaporation = 4.622 kJ/s

    and we know heat absorbed from evaporation = heat remove from water / time

    so time will be 93.7175 / 4.622

    time = 20.27 second
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