A college student wakes up hungry. He turns on the coffee maker (average wattage 1200 W), puts some oatmeal in the microwave oven (1450 W) to cook, puts a couple of slices of bread in the toaster (1146 W), and starts making scrambled eggs in the electric frying pan (1196 W). All of these appliances in his dorm room are supplied by a 120 V (rms) branch circuit protected by a 50 A (rms) circuit breaker.

Determine the total rms current in the current breaker.

Question

Lexie Beltran

Engineering

22 October, 23:20

A college student wakes up hungry. He turns on the coffee maker (average wattage 1200 W), puts some oatmeal in the microwave oven (1450 W) to cook, puts a couple of slices of bread in the toaster (1146 W), and starts making scrambled eggs in the electric frying pan (1196 W). All of these appliances in his dorm room are supplied by a 120 V (rms) branch circuit protected by a 50 A (rms) circuit breaker.

Determine the total rms current in the current breaker.

+4

Answers (1)

Know the Answer?

Angelique Mcmillan · Answer 1

41.6 A

Explanation:

Total power drawn = 1200 W + 1450 W + 1146 W + 1196 W = 4992 W

Power P = IV

I = P/V

Where I is the rms current,

V is the voltage = 120 V

I = 4992/120 = 41.6 A