Using the background information provided and your answers to questions 1 & 2, look at the hex packet below and identify the following: Destination Address: Source Address: Type/Length: Data (aka Payload) : Answer formatting: Include any necessary leading zeros. Use lowercase letters. Only use 1-9 and a-f in your answer (i. e. no special formatting). Packet: 6c40 0889 0448 f832 e4a7 fb38 0806 0001 0800 0604 0002 f832 e4a7 bf38 cOa8 0101 6c40 0889 448 cOa8 01f2 Question 4 Based on the answer in Question 4, the value identified for the Ethernet packet type corresponds to which protocol? [protocol] ARP O IPv4 IPv6

Question

Elizabeth Oneill

Engineering

12 December, 15:59

Using the background information provided and your answers to questions 1 & 2, look at the hex packet below and identify the following: Destination Address: Source Address: Type/Length: Data (aka Payload) : Answer formatting: Include any necessary leading zeros. Use lowercase letters. Only use 1-9 and a-f in your answer (i. e. no special formatting). Packet: 6c40 0889 0448 f832 e4a7 fb38 0806 0001 0800 0604 0002 f832 e4a7 bf38 cOa8 0101 6c40 0889 448 cOa8 01f2 Question 4 Based on the answer in Question 4, the value identified for the Ethernet packet type corresponds to which protocol? [protocol] ARP O IPv4 IPv6

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Madden Irwin · Answer 1

Goal address: Based on the above Ethernet outline design, we get that the goal address begins from the first hex worth and is of size 12 hex values (got from question 1). In light of the bundle given, we get that the goal address is 6c40 0889 c448.

Source address: Similarly, the source address begins after the goal address and is of size 12 hex values (got from question 1). Thus, the appropriate response is f832 e4a7 fb38.

Type/Length: The sort/length begins after the source address and is of size 4 hex values (got from question 1). Thus, the appropriate response is 0806.

Data (Payload) : The data (payload) begins after the sort/length and finishes not long before FCS (Checksum) which is of 4 bytes for example 4 * 2 = 8 hex qualities. So the information comprises of everything between the 'type/length' and 'CRC'. We persuade the CRC to be c0a8 01f2. Henceforth, the appropriate response is 0001 0800 0604 0002 f832 e4a7 bf38 c0a8 0101 6c40 0889 c448.

Question 4:

The Ethernet parcel type characterizes the convention utilized for sending the bundle information. We realize that type 0x0800 demonstrates the IPv4 convention, 0x0806 shows an ARP convention, and 0x86DD demonstrates an IPv6 convention. In light of the appropriate response we got in Question 3, we realize that the sort/length esteem for the given parcel is 0806, which implies that convention utilized for sending the information bundle was ARP convention.