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28 February, 03:36

An empty metal can is heated to 908C and sealed. It is then placed in a room to cool to 208C. What is the pressure inside the can upon cooling? Assume that can contains air under ideal conditions.?

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  1. 28 February, 03:48
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    The pressure inside the can upon cooling is 0.4 atm.

    Explanation:

    Given -

    Initial Temperature, T1 = 908°C = 908 + 273 K = 1181 K

    Final Temperature, T2 = 208°C = 208 + 273 K = 481 K

    Pressure upon cooling, P2 = ?

    Using Gay Lussac's law:

    P1/T1 = P2/T2

    P2 = P1 X T2 / T1

    P2 = 1 atm X 481 / 1181

    P2 = 0.4 atm

    Therefore, the pressure inside the can upon cooling is 0.4 atm.
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