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2 July, 04:48

A bag contains tiles with the letters a-r-i-t-h-m-e-t-i-c. amelia chooses a tile without looking and doesn't replace it. she chooses a second tile without looking. what is the probability that she will choose the letter t both times

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  1. 2 July, 05:01
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    Sample space={A, R, I, T, H, M, E, T, I, C}

    1ST (Choosing T) = = > P (1st draw) = 2/10 = 1/5 = 0.2

    2ND (Choosing again a T) = = > P (2nd draw) = 1/9 = 0.11

    Since it's a conditional probability then P (1st T AND 2nd T) = 0.2 x 0.11 = 0.022
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