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26 May, 16:16

if a normal distribution has a mean of 132 and a standard deviation of 20 what is the value that has a z score of 1.8?

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  1. 26 May, 16:20
    0
    168 = x

    Step-by-step explanation:

    mean = u=132

    standard deviation = sigma = 20

    z score = z=1.8

    The formula is

    z = (x-u) / sigma

    Substituting what we know

    1.8 = (x-132) / 20

    Multiply by 20

    1.8*20 = (x-132) / 20 * 20

    36 = x-132

    Add 132 to each side

    36+132 = x-132+132

    168 = x
  2. 26 May, 16:36
    0
    Multiply the standard deviation by the z-score and add that to the mean:

    Value = 132 + (20*1.8) = 132 + 36 = 168

    The value would be 168.
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