Janet and Nadia each play basketball. Nadia has won twice the number of games Janet has. Is it possible for Janet to have won 10 games if the sum of the games Nadia and Janet have won together is 24? Yes; Janet could have won 10 games because 3x = 24. Yes; Janet could have won 10 games because 2 (10) is less than 24. No; Janet could not have won 10 games because 2x ≠ 24. No; Janet could not have won 10 games because 3x ≠ 24.

Question

Rosa Weeks

Mathematics

8 April, 01:05

Janet and Nadia each play basketball. Nadia has won twice the number of games Janet has. Is it possible for Janet to have won 10 games if the sum of the games Nadia and Janet have won together is 24? Yes; Janet could have won 10 games because 3x = 24. Yes; Janet could have won 10 games because 2 (10) is less than 24. No; Janet could not have won 10 games because 2x ≠ 24. No; Janet could not have won 10 games because 3x ≠ 24.

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Answers (1)

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Nevaeh Clarke · Answer 1

The correct option is option (D).

No; Janet could not have won 10 games because 3x≠24.

Step-by-step explanation:

Given that, Janet and Nadia each play basketball.

Nadia has won twice the number of games Janet.

Let Janet has won x games.

Then Nadia has won = (2x) games.

The sum of the games Nadia and Janet have won together is = 2x+x

=3x.

But given that, the number of games that they have won together is = 24

∴3x=24.

If possible, let Janet has won 10 games.

Then the value x = 10 will satisfy the above equation.

So plugging x=10 in the above equation

3.10 ≠24

No; Janet could not have won 10 games because 3x≠24.