Ask Question
18 December, 23:43

There are 26 prize tickets in a bowl, labeled A to Z. What is the probability that a prize ticket with a vowel will be chosen, not replaced, and then another prize ticket with a vowel will be chosen? Does this represent an independent or dependent event? Explain

+5
Answers (1)
  1. 18 December, 23:57
    0
    3.1%, dependent event

    Step-by-step explanation:

    We have that vowel are 5, it is from A, E, I, O, U therefore the probability of drawing a vowel is:

    5/26

    since there are a total of 26 options to choose from. Then, when selecting that, we are left with 25 options and 4 vowels, therefore the probability would be:

    4/25

    Therefore the final probability is:

    5/26 * (4/25) = 0.031

    In other words, selecting a vowel and then another (without replacement) the probability is 3.1%

    The events are dependent, since the first event affects the second event, since the number of vowels and the number of total options are reduced.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “There are 26 prize tickets in a bowl, labeled A to Z. What is the probability that a prize ticket with a vowel will be chosen, not ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers