There are 26 prize tickets in a bowl, labeled A to Z. What is the probability that a prize ticket with a vowel will be chosen, not replaced, and then another prize ticket with a vowel will be chosen? Does this represent an independent or dependent event? Explain

Question

Shayla Cantu

Mathematics

18 December, 23:43

There are 26 prize tickets in a bowl, labeled A to Z. What is the probability that a prize ticket with a vowel will be chosen, not replaced, and then another prize ticket with a vowel will be chosen? Does this represent an independent or dependent event? Explain

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Answers (1)

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Bruce Donovan · Answer 1

3.1%, dependent event

Step-by-step explanation:

We have that vowel are 5, it is from A, E, I, O, U therefore the probability of drawing a vowel is:

5/26

since there are a total of 26 options to choose from. Then, when selecting that, we are left with 25 options and 4 vowels, therefore the probability would be:

4/25

Therefore the final probability is:

5/26 * (4/25) = 0.031

In other words, selecting a vowel and then another (without replacement) the probability is 3.1%

The events are dependent, since the first event affects the second event, since the number of vowels and the number of total options are reduced.