A^ (2) + b^ (2) + c^ (4) = 2020

Question

Olive Petersen

Mathematics

5 September, 16:19

A^ (2) + b^ (2) + c^ (4) = 2020

+1

Answers (1)

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Velasquez · Answer 1

a=√-c4-b2+2020 or a=-√-c4-b2+2020

b=√-c4-a2+2020 or b=-√-c4-a2+2020

c=cant find it

Step-by-step explanation:

Step 1 for a: Add - c^4 to both sides.

c4+a2+b2+-c4=2020+-c4

a2+b2=-c4+2020

Step 2: Add - b^2 to both sides.

a2+b2+-b2=-c4+2020+-b2

a2=-c4-b2+2020

Step 3: Take square root.

a=√-c4-b2+2020 or a=-√-c4-b2+2020

Step 1 for b: Add - c^4 to both sides.

c4+a2+b2+-c4=2020+-c4

a2+b2=-c4+2020

Step 2: Add - a^2 to both sides.

a2+b2+-a2=-c4+2020+-a2

b2=-c4-a2+2020

Step 3: Take square root.

b=√-c4-a2+2020 or b=-√-c4-a2+2020