How long would it take for a ball dropped from the top of a 256-foot building to hit the ground

Equation for dropping a ball with 0 velocity to begin with.

We know that g is acceleration due to gravity is a constant = (-9.81 m/s^2)

V is velocity at ground

t is time to hit

Y is height dropped from

Equation:

V = (1/2) gt^2 + Y