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21 January, 15:56

Given a possible triangle abc with a=16, b=25 a=22 find a possible value for b round to the nearest tenth.

a. 29.7°

b. 35.8°

c. 139.0°

d. no solution

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Answers (1)
  1. 21 January, 16:08
    0
    We can use the Sine Law:

    a / sin A = b / sin B

    16 / sin 22° = 25 / sin B

    16 / 0.3746 = 25 / sin B

    sin B = 25 · 0.3746 / 16

    sin B = 0.5853

    ∠B = sin^ (-1) 0.5853

    ∠B = 35.83° ≈ 35.8°

    Answer: b. 35.8°
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