Ask Question
9 October, 16:16

Find the direct algebraic relationship between x and y and determine whether this parametric relationship is a function. Simplify as much as possible. x = t^2 - 4t and y = √t + 1

+3
Answers (1)
  1. 9 October, 16:35
    0
    Step-by-step explanation:

    Given:

    x = t^2 - 4t

    y = √t + 1

    Making t the subject of formula from equation 2,

    t = (y - 1) ^2

    Inputting into equation 2,

    x = (y - 1) ^4 - 4 * (y - 1) ^2

    = (y - 1) ^2 ((y - 1) ^2 - 4)

    = (y^2 - 2y + 1) * (y^2 - 2y + 1 - 4)

    = (y^2 - 2y + 1) * (y^2 - 2y - 3)

    = y^4 - 2y^3 - 3y^2 - 2y^3 + 4y^2 + 6y + y^2 - 2y - 3

    x = y^4 - 4y^3 + 2y^2 + 4y - 3

    x = (y - 1) * (y - 1) * (y - 3) * (y + 1)

    The above equation of x and y is a function because the dependent variable, x is dependant on the values of the independent variable, y.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Find the direct algebraic relationship between x and y and determine whether this parametric relationship is a function. Simplify as much ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers